In: Statistics and Probability
(a) Obtain the pmf of X where X is the sum of the two resultant faces
(b) Suppose the two die were rolled many times. Approximately, what would
would be the average of X?
(c) Calculate the standard deviation of X.
total possible outcomes = 4² = 16
a)
outcome | X | P(X) |
(1,1) | 2 | 1/16 |
(1,2)(2,1) | 3 | 2/16 |
(1,3)(3,1)(2,2) | 4 | 3/16 |
(1,4)(4,1)(2,3)(3,2) | 5 | 4/16 |
(2,4)(4,2)(3,3) | 6 | 3/16 |
(3,4)(4,3) | 7 | 2/16 |
(4,4) | 8 | 1/16 |
b)
X | P(X) | X*P(X) | X² * P(X) |
2 | 0.0625 | 0.1250 | 0.2500 |
3 | 0.125 | 0.3750 | 1.1250 |
4 | 0.1875 | 0.7500 | 3.0000 |
5 | 0.25 | 1.2500 | 6.2500 |
6 | 0.1875 | 1.12500 | 6.75000 |
7 | 0.125 | 0.875 | 6.125 |
8 | 0.063 | 0.500 | 4.000 |
P(X) | X*P(X) | X² * P(X) | |
total sum = | 1 | 5 | 27.50 |
average=mean = E[X] = Σx*P(X) = 5
c)
E [ X² ] = ΣX² * P(X) =
27.5000
variance = E[ X² ] - (E[ X ])² =
2.5000
std dev = √(variance) =
1.5811