In: Statistics and Probability
We have given : A sample of n = 16
a population with µ = 30.
sample mean is found to be M = 33.
the sample variance is s2 = 16, therefore s = 4
then conduct a hypothesis test to evaluate the significance of
the treatment effect = (M - µ) / s
= ( 33 - 30) / 4 = 0.75 , it is high
and calculate r2 to measure the size of the treatment effect. = it is not valid for this we need two samples .
Use a two-tailed test with α = .05.
## To test : Ho : µ = 30 vs H1 : µ ≠ 30
## test statistics : t = ( M - µ) * √ (n) / s
t = ( 33 - 30 ) * 4 / 4
t = 3
## t_crit = here degree of freedom is (n-1 ) = 15
used t critical value table : 2.1314 (from table)
## Decision : we reject Ho if t statistics value is greater than t critical value .
here t statistics value is greater than t critical value hence here we reject Ho .
## Conclusion : there is enough evidence to conclude that population mean is differ than 30 ie ( µ ≠ 30)