Question

In a single slit experiment, the central maximum is:

	The same size as all of the other maximums.
	Twice the size of the other maximums.
	Half the size of the other maximums.
	Just slightly larger than the other maximums.

Electrons would be ejected from silver if the incident light had a frequency of:

	1.03 x 1015 Hz
	1.02 x 1015 Hz
	1.01 x 1015 Hz
	None of the options is correct

What is the mass equivalent of an x-ray with a frequency of 5.63 x 1017 Hz?

	4.14 x 10-33 kg
	2.59 x 10-14 kg
	1.24 x 10-24 kg
	None of the options is correct.

Answer 1

In a single slit experiment, the central maximum depends on

if the slit width is doubled then the intensity of central maxima becomes four times and the width fo the central maximum reduces to 1/4 th

the first option never become in single slit experiment

and teh third option also not possible

second option is if we reduced the slit width to half then the central maximum will be twice the size of the other maximums

so the answer is option B

----------

we know that

work function of silver is w = 4.2 ev = 4.2*1.6*10^-19 J = 6.72*10^-19 J

W = h*f

f = W/h

f = 6.72*10^-19/ (6.625*10^-34) Hz

f = 1.01434*10^15 Hz

Electrons would be ejected from silver if the incident light had a frequency of

f = 1.01434*10^15 Hz <<<-----ANSWER

so the answer is third option

3.

Given X ray frequency f = 5.63*10^17 Hz

we know from de Broglie wavekength is

Lambda = h/mv

c/f = h/mv

hf = mc^2

m = hf/c^2

m = (5.63*10^17*6.625*10^-34) /(3*10^8)^2 kg

m = 4.14431*10^-33 kg

so the answer is 4.14431*10^-33 kg