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Find the work done by the force field F(x,y) = <2xy-cosx,ln(xy)+cosy> along the path C, where...

Find the work done by the force field F(x,y) = <2xy-cosx,ln(xy)+cosy> along the path C, where C starts at (1,1)(1,1) and travels to (2,4)(2,4) along y=x^2, then travels down to (2,2)(2,2) along a straight path, and returns to (1,1)(1,1) along a straight path. Fully justify your solution.

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Colby Messinger answered 1 year ago
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