Question

In: Mechanical Engineering

A Projectile is shot at a moving target with initial velocity Vo=2000ft/s. The target is moving...

A Projectile is shot at a moving target with initial velocity Vo=2000ft/s. The target is moving at 500ft/s and its initial start was (Xo, Yo)= 200',300' at angle phi=15. the weight of the target is 5lbf. Gravity is 32.3 ft/s^2. Find angle theta the projectile would need to be shot to hit the target. No drag. There is the high angle case and low angle

Solutions

Expert Solution

Let the angle with which the projectile is fired be

The horizontal distance covered by the projectile at a time instace t is:

The vertical position of the projectile is

The horizontal and vertical positions of the target are:

At the instance when the projectile hits the target, the horizontal and vertical positions of both the projectile and the target should be the same.

and

=>

Squaring the equations and adding them gives

Taking the positive value for time, t = 0.225777 and equating the hortizontal positions, value of can be calculated.

The angle at which the projectile has to be shot is 46.81° and the impact occurs after 0.22577 seconds.


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