Question

Explain why a simple exergonic free energy diagram would not be sufficient for cellular respiration with the following equation: C6H12O6 + 6O2 → 6CO2 +6H2O + 36 ATP

Explain where the C in CO2 comes from when you exhale. Be specific.

Please, i would appreciate an answer in a text form not handwritten. thank you

Answer 1

A series of metabolic steps used to extract the energy from the organic molecules like glucose is called cellular respiration.

In aerobic respiration one glucose molecule (6 Carbon compound) first degraded by the glycolysis in the cytoplasm of the cell into two molecules of pyruvate (3 Carbon compound). During degradation of glucose produces two molecules of NADH2 and four ATPs but two ATPs are utilized in glycolysis process so the net gain is two ATPs at the end of glycolysis. The two pyruvate molecules are next converted to acetyl coenzyme A and two NADH molecules are generated. Later the acetyl coenzyme A further degraded via Kreb’s cycle and produce two GTP, two FADH2, six NADH2 are produced from two molecules of private. Generation of ATP by the oxidation of NADH2 and FADH2 by electron transport chain is called oxidative phosphorylation. During the aerobic respiration total, 36 ATPs are produced.

C6H12O6 + 6O2 → 6CO2 +6H2O + 36 ATP

It is the equation for glucose oxidation in aerobic respiration.

In glycolysis, every time third carbon and fourth carbon of glucose is oxidized and released as a CO2. When glucose enters into glycolysis converted to 2 molecules of pyruvate which is converted to acetyl coenzyme A. now it enters into Kreb’s cycle. In Kreb’s cycle, it combines with the oxaloacetate form citrate. The citrate degraded by Kreb’s cycle enzymes. During the degradation of glucose the third carbon and fourth carbon of pyruvate generated during glycolysis released as a CO2 at the time of exhalation.