In: Advanced Math
Recall that a set B is dense in R if an element of B can be found between any two real numbers a < b. Take p∈Z and q∈N in every case. It is given that the set of all rational numbers p/q with 10|p| ≥ q is not dense in R. Explain, using plain words (without a rigorous proof), why this is. That is, present a general argument in plain words. Does this set violate the Archimedean Property? If so, how? (PLEASE DON'T REPEAT THE ANSWERS TO THIS QUESTION ALREADY POSTED ON CHEGG)
Sorry, I don't know about the previous answers. I hope this one is clear to you.
Let
.
If
is dense in
then by defenition, for ANY real number a and b,
a<b, we can find an element in
.
Now, we have to prove that
is not dense in
.
For that it is enough to prove that
.
----------------------------(i)
So let me choose
Then clearly
which means if we choose
,
we cannot find an element of
between
.
ARCHIMEDEAN PROPERTY
For any
and
, there is an
so
that
which is equivalent to
.
doesnot satisfies Archimedean property.
Because,
For any natural number
,
there exists a positive real number
where
such that
, which is a contradiction to Archimedean property.