In: Statistics and Probability
A. A type I error was made
B. The abuse of bath salts increases fecal incontinence.
C. The abuse of bath salts is associated with bowel control.
D. A clinically significant association was found.
Solution:
The given chi square is the value of the chi square test statistic for testing the independence of two attributes.
For the given scenario, the null and alternative hypotheses will be as follows:
Null hypothesis : The abuse of salts is not associated with bowel control.
Alternative hypothesis : The abuse of salts is associated with bowel control.
The value of the test statistic is 32.8 and the p-value for the test statistic is 0.005.
We make decision rule as follows:
If p-value is greater than the significance level, then we fail to reject the null hypothesis.
If p-value is less than the significance level, then we reject the null hypothesis.
Generally significance level of 0.01, 0.05 or 0.10 are used. Suppose, our significance level is 0.01.
p-value = 0.005 and significance level = 0.01
(0.005 < 0.01)
Since, p-value is less than the significance level of 0.01, therefore we shall reject the null hypothesis.
Conclusion : The abuse of bath salts is associated with bowel control.
Hence, option (C) is correct.
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