Question

A bag of 28 tulip buds contains 11 red tulip buds, 11 yellow tulip buds, and 6 purple tulip buds

​(a) What is the probability that two randomly selected tulip bulbs are both​ red? Round answer to three decimal places

​(b) What is the probability that the first bulb selected is red and the second​ yellow? Round answer to three decimal places

​(c) What is the probability that the first bulb selected is yellow and the second​ red? Round answer to three decimal places

​(d) What is the probability that one bulb is red and the other​ yellow? Round answer to three decimal places

Thank you! :)

Answer 1

(a) What is the probability that two randomly selected tulip bulbs are both​ red? Round answer to three decimal places

Probability first bulb is red = 11/28

There are not 10 red bulbs left and 27 total bulbs left
Probability second bulb is red = 10/27

P =(11/28)*(10/27) = 0.146

​(b) What is the probability that the first bulb selected is red and the second​ yellow? Round answer to three decimal places

Probability first bulb is red = 11/28
Probability second bulb is yellow = 11/27

P = (11/28) * (11/27) = 0.160

​(c) What is the probability that the first bulb selected is yellow and the second​ red? Round answer to three decimal places

Probability first bulb is yellow = 11/28
Probability second bulb is red = 11/27

P = (11/28) * (11/27) = 0.160

​(d) What is the probability that one bulb is red and the other​ yellow? Round answer to three decimal places

sum the answer from b and c

=0.160 + 0.160 = 0.320