In: Statistics and Probability
A manufacturer makes steel rods that are supposed to have a mean length of 50 cm. A retailer suspects that the bars are running short. A sample of 40 bars is taken and their mean length is determined to be 49.4 cm with a standard deviation of 3.6 cm. Test the retailer’s claim that the mean length is less than 50 cm. Use a one percent level of significance.
1. What test should be used for this problem?
2. What is the P-value?
3.
What's the conclusion?
A. |
Fail to reject H0. There is not enough evidence to support the claim that the mean length is less than 50 cm. |
|
B. |
Fail to reject H1. There is enough evidence to support the claim that the mean length is less than 50 cm. |
|
C. |
Reject H0. There is enough evidence to support the claim that the mean length is less than 50 cm. |
|
D. |
Reject H1. There is not enough evidence to support the claim that the mean length is more than 50 cm. |
Solution :
t test should be used for this problem
This is the left tailed test .
The null and alternative hypothesis is
H0 : = 50
Ha : < 50
Test statistic = t
= ( - ) / s / n
= (49.4 - 50) / 3.6 / 40
Test statistic = -1.054
df = 39
P-value = 0.1492
= 0.01
P-value >
Fail to reject the null hypothesis .
Option A) is correct .