In: Statistics and Probability
Consider the experimental results for the following randomized block design. Make the calculations necessary to set up the analysis of variance table.
Treatments | ||||
---|---|---|---|---|
A | B | C | ||
Blocks | 1 | 10 | 9 | 8 |
2 | 12 | 6 | 5 | |
3 | 18 | 16 | 14 | |
4 | 20 | 18 | 18 | |
5 | 8 | 7 | 8 |
Use α = 0.05 to test for any significant differences.
Find the value of the test statistic. (Round your answer to two decimal places.)
__________.
Find the p-value. (Round your answer to three decimal places.)
p-value = ________.
For this question we use MS-EXCEL.
Go to data analysis toolpack and select ANOVA : two factors without replication.
Randomized Block Design
Test hypothesis is,
H01 : There is no significant difference between treatments.
H11 : There is significant difference between treatments.
H02 : There is no significant difference between blocks.
H12 : There is significant difference between blocks.
ANOVA Table
Source of Variation | SS | df | MS | F | P-value | F crit |
Treatments(columns) | 25.2 | 2 | 12.6 | 6 | 0.0256 | 4.45897 |
Blocks(rows) | 320.4 | 4 | 80.1 | 38.14286 | 2.96E-05 | 3.837853 |
Error | 16.8 | 8 | 2.1 | |||
Total | 362.4 | 14 |
level of significance = 0.05
For treatements
The value of test statistic is 6
p-value is 0.0256
Therefore, p-value <
Hence, Reject H01
Conclusion : There is significant difference between treatments.
For Blocks
The value of test statistic is 38.14286
p-value is 2.96E-05
Therefore, p-value <
Hence, Reject H02
Conclusion : There is significant difference between blocks.