In: Statistics and Probability
Consider the experimental results for the following randomized block design. Make the calculations necessary to set up the analysis of variance table.
Treatments | ||||
---|---|---|---|---|
A | B | C | ||
Blocks | 1 | 10 | 9 | 8 |
2 | 12 | 6 | 5 | |
3 | 18 | 15 | 14 | |
4 | 20 | 18 | 18 | |
5 | 8 | 7 | 9 |
Use α = 0.05 to test for any significant differences.
State the null and alternative hypotheses.
H0: μA ≠
μB ≠ μC
Ha: μA =
μB = μC
H0: At least two of the population means are
equal.
Ha: At least two of the population means are
different.
H0: μA =
μB = μC
Ha: μA ≠
μB ≠ μC
H0: μA =
μB = μC
Ha: Not all the population means are equal.
H0: Not all the population means are
equal.
Ha: μA =
μB = μC
Find the value of the test statistic. (Round your answer to two decimal places.)
Find the p-value. (Round your answer to three decimal places.)
p-value =
State your conclusion.
Reject H0. There is sufficient evidence to conclude that the means of the three treatments are not equal.
Reject H0. There is not sufficient evidence to conclude that the means of the three treatments are not equal.
Do not reject H0. There is not sufficient evidence to conclude that the means of the three treatments are not equal.
Do not reject H0. There is sufficient evidence to conclude that the means of the three treatments are not equal.
Applying 2 way ANOVA":
from above:
H0: μA =
μB = μC
Ha: Not all the population means are equal.
value of the test statistic. =4.98
p-value =0.039
since p value <0.05
Reject H0. There is sufficient evidence to conclude that the means of the three treatments are not equal.