In: Chemistry
The sulfate ion level in a municipal water supply is given as
46.0ppm .
What is [SO2?4] in this water? in units M
Given the level of sulfate ion is 46.0 ppm
= 46.0 mg / L
Molar mass of sulfate ion , SO42- is = At.mass of S + (4xAt.mass of O )
= 32 + (4x16)
= 96 g/mol
So the concentration of sulfate ion is = [SO42- ] = 46.0 mg / L
= 46.0x10-3 g / L Since 1g = 103 mg
= 46.0x10-3 gx(1/96)(mol/g) /L
= 4.79x10-4 mol/L
= 4.79x10-4 M