In: Statistics and Probability
Question 2
An operations manager of a large firm is studying the monthly sales (in $’000) of three subsidiary companies over a six-month period as given in the table below.
Company A |
Company B |
Company C |
152 |
148 |
150 |
135 |
158 |
148 |
130 |
136 |
126 |
142 |
138 |
128 |
125 |
140 |
140 |
128 |
127 |
135 |
At the 0.01 significance level, can we conclude that there is a difference in the means of monthly sales of the three subsidiary companies over a six-month period?
b) Calculate the level of significance, critical value and rejection region
A. |
dfc = 5 |
|
B. |
dfc = 2 |
|
C. |
dfc = 2 |
|
D. |
dfc = 2 |
Ho :
Ha : Atleast two population means differs from
each other.
Level of Significance (l.o.s.) : = 0.01
Decision Criteria : Reject Ho at 1% l.o.s. if F
> F crit,
where F crit = F (,
k-1, n-k) = F (0.01, 2,15) = 6.359
Calculation : To determine the results, we make use of Excel & the steps are :
Step 1 : Enter the data in excel.
Step 2 : Select "Anova : Single Factor" function
fro the data analysis package available under the data tab of
excel.
Step 3 : Enter the range of the data in the first
cell & change the l.o.s. from 0.05 to 0.01
Step 4 : Click ok & thus, following results
are obtained :
Anova: Single Factor | ||||||
SUMMARY | ||||||
Groups | Count | Sum | Average | Variance | ||
Company A | 6 | 812 | 135.3333333 | 102.2666667 | ||
Company B | 6 | 847 | 141.1666667 | 113.7666667 | ||
Company C | 6 | 827 | 137.8333333 | 100.1666667 | ||
ANOVA | ||||||
Source of Variation | SS | df | MS | F | P-value | F crit |
Between Groups | 102.7777778 | 2 | 51.38888889 | 0.487560616 | 0.62352407 | 6.359 |
Within Groups | 1581 | 15 | 105.4 | |||
Total | 1683.777778 | 17 |
i.e. option C.
Conclusion : Since F < F crit, we do not reject Ho at 1% l.o.s. & thus, conclude that there is no significant difference in the means of monthly sales of the three subsidiary companies over a six-month period.
Hope this answers your query!