120 g + 18˚ water is in a calorimeter, whose heat capacity is 50 J /...

120 g + 18˚ water is in a calorimeter, whose heat capacity is 50 J / ˚C. Clarification is done by calculating what happens when 36 g of ice of 0 ˚C is added in the calorimeter.

(Answer T = 0 ˚C, remaining approximately 6 g of ice)

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genius_generous answered 1 year ago

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