Solve the given initial-value problem. y'' + 4y' + 4y = (5 +
x)e^(−2x) y(0) = 3, y'(0) = 6
Arrived at answer
y(x)=3e^{-2x}+12xe^{-2x}+(15/2}x^2e^{-2x}+(5/6)x^3e^{-2x) by using
variation of parameters but it was incorrect.
FIND THE GENERAL SOLUTION TO THE DE: Y”’ + 4Y” – Y’ –
4Y = 0
COMPUTE:
L {7 e 3t – 5 cos ( 2t ) – 4 t 2
}
COMPUTE:
L – 1 {(3s + 6 ) / [ s ( s 2 + s – 6 ) ]
}
SOLVE THE INITIAL VALUE PROBLEM USING LAPLACE
TRANSFORMS:
Y” + 6Y’ + 5Y = 12 e t
WHEN : f ( 0 ) = -...