In: Statistics and Probability
The percentage of titanium in an alloy used in aerospace castings is measured in 51 randomly selected parts. The sample standard deviation is s = 0.40. Construct a 95% two-sided confidence interval for σ. Assume population is approximately normally distributed.
Round your answers to 4 decimal places.
Solution :
Given that,
s = 0.40
s2 = 0.6325
n = 51
Degrees of freedom = df = n - 1 = 51 - 1 = 50
At 95% confidence level the
2 value is ,
= 1 - 95% = 1 - 0.95 = 0.05
/ 2 = 0.05 / 2 = 0.025
1 -
/ 2 = 1 - 0.025 = 0.975
2L
=
2
/2,df
= 71.420
2R
=
21 -
/2,df = 32.357
The 95% confidence interval for
is,
(n
- 1)s2 /
2
/2
<
<
(n - 1)s2 /
21 -
/2
(50)(0.6325)
/ 71.420 <
<
(52)(0.6325) / 32.357
0.6654 <
< 0.9886
(0.6654 , 0.9886)