In: Statistics and Probability
Two catalysts are being analyzed to determine how they affect the mean yield of a chemical process. Specifically, catalyst 1 is currently used. Because catalyst 2 is cheaper, it should be adopted, if it does not change the process yield. A test is run in the pilot plant and results in the data shown in the Table below. Both populations are assumed normal.
a) Assuming equal variances, using a hypothesis test at 5% alpha level, show if there is any difference in the mean yields.
b) Assuming unequal variances, using a hypothesis test at 5% alpha level, show if catalyst 2 yields greater mean than catalyst 1.
c) Find a 95% confidence interval for the mean of catalyst 1 minus that of catalyst 2 assuming equal variances.
Observation# |
Catalyst 1 |
Catalyst 2 |
1 |
91.5 |
89.19 |
2 |
94.18 |
90.95 |
3 |
92.18 |
90.46 |
4 |
95.39 |
93.21 |
5 |
91.79 |
97.19 |
6 |
89.07 |
97.04 |
7 |
94.72 |
91.07 |
8 |
89.21 |
92.75 |
First we need to find the mean and SD of both data sets:
Descriptive statistics | ||
Catalyst 1 | Catalyst 2 | |
count | 8 | 8 |
mean | 92.2550 | 92.7325 |
sample standard deviation | 2.3850 | 2.9835 |
sample variance | 5.6883 | 8.9010 |
minimum | 89.07 | 89.19 |
maximum | 95.39 | 97.19 |
range | 6.32 | 8 |
(a)
Conclusion: We cannot conclude that there is any difference in the mean yields..
(b)
Conclusion: We cannot conclude that catalyst 2 yields greater mean than catalyst 1.
(c)