Calculate the osmolarity of 1 L D51/4NS with 15 mEq KCL (round your answer to the...

Calculate the osmolarity of 1 L D51/4NS with 15 mEq KCL (round your answer to the closest whole number)

Expert Solution

Let us first convert mEq miliequivalents into grams.

Formula,

mEq = (Mass in grams * Valence of salt KCll / Molecular weight of KCl) ..... (1)

For KCl soluton,

mEq = 15, Molar mass = 74.5 g/mol, Valency of KCl = 1

Placing all values in above formula,

15 = Mass of KCl * 1 / 74.5

Mass of KCl = 15 * 74.5 = 1117.5 mg = 1.1175 g

# of moles of KCl = Mass of KCl / Molar mass of KCl = 1.1175 / 74.5 = 0.015 moles.

KCl ionizes into 2 ions per molecule.

# of osmols of KCl = 2 * # of moles of KCl = 2 * 0.015 = 0.30 osmol.

Osmolarity of KCl solution = # of osmoles / Volume in L = 0.30 osmol / 1.0 L = 0.30 osmol/L.

Osmolarity of given D51/4NS is 0.30 osmolar.

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queen_honey_blossom answered 2 years ago

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