A physician orders 40 mEq of KCL added to one L of D5NS IV torun...

A physician orders 40 mEq of KCL added to one L of D5NS IV to run over 12 hours.

Potassium chloride for injection is available in 2 mEq/mL.

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How many mL of KCl need to be added to the IV?

•

What is the total number of mL in the IV?

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What is the flow rate in mL/hr?

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How many mEq of KCl will the patient receive each hour?

Solutions

Expert Solution

1- requirement of Kcl =40mEq for 12 hour.

Kcl solution contain 2mEq/ml.

Volume of Kcl solution needed=40mEq/2mEq/ml.=20 ml.

2-total amount of fluid in iv =1L of D5NS +20ml of Kcl solution.

1000ml+20ml=1020ml

3- since 1020 ml of fluid is to be imfused within 12 hour.

So rate of flow ml /hr =1020/12=85ml/hr.

4- patient is getting 40mEq of Kcl in 12 hour.

So mEq of kcl/hr = 40/12=3.33mEq/hour.

Nightingale answered 2 years ago

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