Question

In: Statistics and Probability

A professor tests whether the loudness of noise during an exam (low, medium, and high) is...

A professor tests whether the loudness of noise during an exam (low, medium, and high) is independent of exam grades (pass, fail). The following table shows the observed frequencies for this test.

Noise Level

Low Medium High

Exam Pass 20 18 8 46

Fail 8 6 10 24

28 24 18 N=70

(a) Conduct a chi-square test for independence at a 0.05 level of significance. (Round your answer to two decimal places.)

x^2{obt}=

(b) Compute effect size using Cramer's V. (Round your answer to two decimal places.)

V =

Solutions

Expert Solution

In order to test , whether the loudness of noise during an exam (low, medium, and high) is independent of exam grades (pass, fail) we define the test hypothesis as:

Null hypothesis:

Test grade and noise level are independent.

Against the alternative hypothesis is

Test grade and noise level are not independent.

Observed data (frequency) are as follows:

Noise Level
Low Medium High
exam Pass 20 18 8 46
Fail 8 6 10 24
28 24 18 70

Now the expected data (frequency) are calculated as:

Expected frequency=(Row total X Colunm total) / Grand total

Noise Level
Low Medium High Sum
exam Pass 18.4 15.77143 11.82857 46
Fail 9.6 8.228571 6.171429 24
28 24 18 70

To calculate the Chi square test statistics we define the chi square as:

Noise Level
Low Medium High Sum
exam Pass 21.73913 20.54348 5.410628 47.69324
Fail 6.666667 4.375 16.2037 27.24537
sum 28.4058 24.91848 21.61433 74.93861

=74.93861-70

=4.93861

Now as it is a contingency table view , therefore the degree of freedom of statistics is;

Therefore the critical value of test statistics at level of significance is:

from the standard chi square table .

in order to determined the P value for corresponding Chi square we follow Excell as:

=CHIDIST(4.9386,2)

Therefore ,

and corresponding

We fail to reject the null hypothesis and therefore we retain the null hypothesis.

b) Cramer’s V is measure the inter correlation between two contingency ( discrete variables). It is use to post test of strengths of association after chi-square significance for more than 2x2 rows and columns.

It is denoted as:

r: row and c: column

r: row and c: column

=0.07055

Therefore the effect size by cramer's V is :

V=0.07


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