In: Math
Write down an augmented matrix in reduced form corresponding to a system with 3 equations and 5 variables which has infinitely many solutions and 2 free variables.
Write down an augmented matrix in reduced form corresponding to a system with 4 equations and 5 variables which has no solutions and 2 free variables.
1. Let A be the augmented matrix of a system with 3 equations and 5 variables which has infinitely many solutions and 2 free variables. Then A is a 3 X 6 matrix.
Let the RREF of A be
1 |
0 |
0 |
-1 |
-2 |
3 |
0 |
1 |
0 |
-2 |
-1 |
4 |
0 |
0 |
1 |
-3 |
-1 |
5 |
Now, if X = (x,y,z,w,u)T, then the system AX = b , where b is a non-zero vector , is equivalent to x-w-2u = 3 or, x = 3+w+2u, y-2w-u = 4 or, y = 4+2w+u and z-3w-u = 5 or, z = 5+3w+u.
Then , X = (3+w+2u,4+2w+u,5+3w+u,w,u)T = (3,4,5,0,0)T +w(1,2,3,1,0)T+u(2,1,1,0,1)T.
As may be observed, the linear system AX = b is a system with 3 equations and 5 variables which has infinitely many solutions and 2 free variables.
2. Let A be the augmented matrix of a system with 4 equations and 5 variables which has no solutions. Such a system cannot have any free variables as it is inconsistent. A system can have free variables only if it is consistent and has infinitely many solutions.