Question

In: Statistics and Probability

For questions #12-20, refer to the following: Four diet plans were compared to see who lost...

For questions #12-20, refer to the following: Four diet plans were compared to see who lost the most weight (lbs) over the same time period with the following results:

diet #1: 25, 36, 30, 45, 18, 5, 21, 33

diet #2: 12, 40, 50, 55, 27, 8, 16

diet #3: 28, 69, 42, 8

diet #4: 12, 18, 25, 25, 36, 48

test with a 1% significance level to see if the weight loss was different for the plans.

#12) What is the value for SSW?

a.

528,264.05
b.

156.85
c.

27,611.91
d.

5997.39
e.

4867.42

What is the value for SSB?

a.

158.62
b.

303.65
c.

291.85
d.

22270.27
e.

6301.04

What is the value for MSW?

a.

237.45
b.

1060.49
c.

285.59
d.

213.36
e.

258.76

What is the value for MSB?

a.

78.12
b.

68.35
c.

295.60
d.

101.22
e.

92.46

What is the value of the test statistic?

a.

.35
b.

2.80
c.

3.12
d.

2.36
e.

2.82

What is the degree of freedom for the numerator?

a.

2
b.

21
c.

3
d.

4
e.

25

What is the degree of freedom for the denominator?

a.

25
b.

21
c.

4
d.

3
e.

22

What is the critical value for this ANOVA test?

a.

2.36
b.

3.00
c.

4.87
d.

3.12
e.

2.80

What is the conclusion to this test of ANOVA?

a.

Accept Ho : the means of the categories are the same
b.

Reject Ho : the means of the categories are the same
c.

Reject H1 : the means of the categories are significantly different
d.

Accept Ho: the means of the categories are significantly different
e.

Reject Ho : the means of the categories are significantly different

A contingency table used for a hypothesis test that contains 6 columns and 3 rows will have what degree of freedom?

a.

12
b.

18
c.

10
d.

not enough information provided to answer
e.

15

Rejecting Ho for a test of Independence means?

a.

the 2 questions are not the same
b.

the 2 questions are independent
c.

the means of the 2 questions are different
d.

the categories are not evenly distributed
e.

the 2 questions are dependent

Solutions

Expert Solution

Anova: Single Factor
SUMMARY
Groups Count Sum Average Variance
Diet 1 8 213 26.625 150.5536
Diet 2 7 208 29.71428571 356.2381
Diet 3 4 147 36.75 656.9167
Diet 4 6 164 27.33333333 167.0667
ANOVA
Source of Variation SS df MS F P-value F crit
Between Groups 303.6531 3 101.22 0.35 0.786418 3.072467
Within Groups 5997.387 21 285.59
Total 6301.04 24

I Have used Excel Data > Data analysis > Anova :Single factor > select the data > ok

_____________________

SSW = 5997.39(d)

___________________

SSB = 303.65 (b)

__________________

MSW = 285.59(C)

__________________

MSB = 101.22 (d)

_________________

Test - stats (F) = 0.35(a)

_________________

df(numerator ) = 3 (C)

__________________

df(Denominator) = 21(b)

___________________

Fcritical = 3.07 nearest answer = (d) 3.12 if incorrect try (b) 3.00

____________________

a.

Accept Ho : the means of the categories are the same

________________________

degree of freedom = (number of column-1)(number of rows -1)

= (5)*(2) = 10 (c)

____________________________

(c) the means of the 2 questions are different

orchestra answered 1 year ago
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