Question
In: Chemistry
Consider a galvanic cell based on the following line notation at 295 K: Fe|Fe3+||Cu2+|Cu where the...
Consider a galvanic cell based on the following line notation at 295 K:
Fe|Fe3+||Cu2+|Cu
where the standard cell potential is 0.38 V. What will the following changes do to the potential of the cell?
a) Add water to the anode portion of the cell
increase potential
decrease potential
no change in potential
b) Add equal amounts of water to both the anode and cathode portions of the cell
increase potential
decrease potential
no change in potential
c) Increase the mass of the Cu
increase potential
decrease potential
no change in potential
Solutions
queen_honey_blossom answered 2 years agoRelated Solutions
Consider a cell based on the following line notation at 298 K: Cu | Cu2+ (0.237...
Consider a cell based on the following line notation at 298
K:
Cu | Cu2+ (0.237 M) || Ni2+ (1.29 M) |
Ni
Given:
Cu2+ + 2 e- →
Cu Eo = 0.34 V
Ni2+ + 2 e- →
Ni Eo = -0.23 V
How many of the following responses are true?
1. Decreasing the concentration of the Cu2+ will
increase the concentration of the reaction
2. Using a Pt electrode in place of the Cu electrode will not
change the potential...
Consider a galvanic cell based upon the following half reactions: Cu2+ + 2e- → Cu 0.34...
Consider a galvanic cell based upon the following half
reactions: Cu2+ + 2e- → Cu 0.34 V Fe3+ + 3e- → Fe -0.0036 V How
many of the following responses are true? 1. Decreasing the
concentration of Cu2+ (assuming no volume change) will decrease the
potential of the cell 2. Increasing the concentration of Fe3+
(assuming no volume change) will increase the potential of the cell
3. Adding equal amounts of water to both half reaction vessels will
increase the...
Consider a galvanic cell based on the following two half reactions at 298 K: SRP Fe3+...
Consider a galvanic cell based on the following two half
reactions at 298 K: SRP Fe3+ + e- Fe2+ 0.77 V Cu2+ + 2 e- Cu
0.34 V How many of the following changes will increase the
potential of the cell? Why?
1. Increasing the concentration of Fe+3 ions
2. Increasing the concentration of Cu2+ ions
3. Removing equal volumes of water in both half reactions
through evaporation
4. Increasing the concentration of Fe2+ ions
5. Adding a...
Consider a galvanic cell based on the following line notation at standard conditions and 298K: Sn...
Consider a galvanic cell based on the following line notation at
standard conditions and 298K:
Sn | Sn2+ || Fe3+ | Fe
Which of the following changes WILL NOT change the potential of the
cell?
Add equal amounts of water to each half cell
Replace the Fe electrode with a Pt electrode
Increase the concentration of Sn2+
Decrease the concentration of Fe3+
Replace the Sn electrode with a Pt electrod
Consider a galvanic cell based in the reaction Fe2+ + Cr2O72- → Fe3+ + Cr3+ in...
Consider a galvanic cell based in the reaction Fe2+ +
Cr2O72- → Fe3+ +
Cr3+ in acidic solution. What is the coefficient of
Fe3+in the balanced equation?
Reference: Ref 18-2
Select one:
a.
3
b.
4
c.
none of these
d.
6
e.
2
1. A galvanic cell is based on the following half-reactions at 285 K: Ag+ + e-...
1. A galvanic cell is based on the following half-reactions at
285 K:
Ag+ + e- →
Ag Eo = 0.803
V
H2O2 (aq) + 2 H+ + 2 e-
→ 2 H2O Eo =
1.78 V
What will the potential of this cell be when [Ag+] =
0.571 M, [H+] = 0.00341 M, and
[H2O2] = 0.895 M?
Please show full work .
A concentration cell based on the following half reaction at 318 K Cu2+ + 2 e-...
A concentration cell based on the following half reaction at 318
K
Cu2+ + 2 e- → Cu SRP = 0.340 V
has initial concentrations of 1.31 M Cu2+, 0.291 M Cu2+, and a
potential of 0.02061 V at these conditions. After 8.1 hours, the
new potential of the cell is found to be 0.006576 V. What is the
concentration of Cu2+ at the cathode at this new potential?
Calculate E at 25° C for a galvanic cell based on the reaction: Zn(s) + Cu2+(aq)→Zn...
Calculate E at 25° C for a galvanic cell based on the
reaction:
Zn(s) + Cu2+(aq)→Zn
2+(aq) + Cu (s) in which
[Zn2+]=0.55M and [Cu2+]=1.02M
A galvanic cell is set up as follows: Zn|Zn2+(0.01 mol/L)||Cu2+(0.1 mol/L)|Cu. How will the voltage of...
A galvanic cell is set up as follows:
Zn|Zn2+(0.01
mol/L)||Cu2+(0.1 mol/L)|Cu.
How will the voltage of the cell be affected by each of the
following change:
(a) increase Cu+2 concentration to 1mol/L;
(b) decrease Zn2+ concentration to 0.0001
mol/L;
Calculate the cell potential for the following electrochemical cell: Zn | [Zn2+]=4.2M || [Cu2+]=0.004M | Cu
Calculate the cell potential for the following electrochemical cell:
Zn | [Zn2+]=4.2M || [Cu2+]=0.004M | Cu
ADVERTISEMENT
ADVERTISEMENT
Latest Questions
- You have invested 30 percent of your portfolio in Jacob, Inc., 40 percent is Bella Co.,...
- Parallel Arrays This question is in MindTap Cengage Summary In this lab, you use what you...
- 5. You have invested 30 percent of your portfolio in Jacob, Inc., 40 percent is Bella...
- JAVA Write a test program that prompts the user to enter a series of integers and...
- (2) Cite an example on how organizations like Google, Facebook, Youtube etc collect data for image...
- The legal landscape is perpetually changing. Psychologists must remain abreast of these changes to avoid potentially...
- We are evaluating a project that costs $1.68 million, has a six-year life, and has no...
ADVERTISEMENT