A sample of 11.8 liters of an ideal gas at 24.0°C and 725 torr is compressed...

A sample of 11.8 liters of an ideal gas at 24.0°C and 725 torr is compressed and heated so that the volume is 6.6 liters and the temperature is 73.0°C. What is the pressure in the container?

Solutions

Expert Solution

moles of gas (n) = PV/RT

with,

P = 725/760 = 0.954 atm

V = 11.8 L

R = gas constant

T = 273 + 24 = 294 K

we get,

moles of gas (n) = 0.954 x 11.8/0.08205 x 294 = 0.47 mol

when, volume is changed to 6.6 L and temperature to 273 + 73 = 346 K

Pressure in the container = nRT/V

= 0.47 x 0.08205 x 346/6.6

= 2.02 atm

queen_honey_blossom answered 1 year ago

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