Question

In: Statistics and Probability

Data on oxide thickness of semiconductors are as follows: 424 430 416 417 421 434 417...

Data on oxide thickness of semiconductors are as follows:

424 430 416 417 421 434 417 409 432 431 423 426 412 437 436 426 413 426 408 439 422 426 412 417



Consider this dataset as the population, not a sample.

(a) Calculate a point estimate of the mean oxide thickness for all wafers in the population. (Round your answer to 3 decimal places.)

(b) Calculate a point estimate of the standard deviation of oxide thickness for all wafers in the population. (Round your answer to 2 decimal places.)

(c) Calculate the standard error of the point estimate from part (a). (Round your answer to 2 decimal places.)

(d) Calculate a point estimate of the median oxide thickness for all wafers in the population. (Express your answer to 1 decimal places.)

(e) Calculate a point estimate of the proportion of wafers in the population that have oxide thickness greater than 430 angstrom. (Round your answer to 4 decimal places.)

Solutions

Expert Solution

a.

b.

Create the following table.

data data-mean (data - mean)2
424 0.91669999999999 0.84033888999998
430 6.9167 47.84073889
416 -7.0833 50.17313889
417 -6.0833 37.00653889
421 -2.0833 4.34013889
434 10.9167 119.17433889
417 -6.0833 37.00653889
409 -14.0833 198.33933889
432 8.9167 79.50753889
431 7.9167 62.67413889
423 -0.0833 0.00693889
426 2.9167 8.50713889
412 -11.0833 122.83953889
437 13.9167 193.67453889
436 12.9167 166.84113889
426 2.9167 8.50713889
413 -10.0833 101.67293889
426 2.9167 8.50713889
408 -15.0833 227.50593889
439 15.9167 253.34133889
422 -1.0833 1.17353889
426 2.9167 8.50713889
412 -11.0833 122.83953889
417 -6.0833 37.00653889

Find the sum of numbers in the last column to get.

So standard deviation is

c. Standard error is

d. The median is the middle number in a sorted list of numbers. So, to find the median, we need to place the numbers in value order and find the middle number.

Ordering the data from least to greatest, we get:

408   409   412   412   413   416   417   417   417   421   422   423   424   426   426   426   426   430   431   432   434   436   437   439   

As you can see, we do not have just one middle number but we have a pair of middle numbers, so the median is the average of these two numbers:

Median=

e. Let us first arrange the data

408
409
412
412
413
416
417
417
417
421
422
423
424
426
426
426
426
430
431
432
434
436
437
439

So out of 24, we see that 6 are above 430, so


Related Solutions

Data on oxide thickness of semiconductors are as follows: 424 431 414 417 420 434 420...
Data on oxide thickness of semiconductors are as follows: 424 431 414 417 420 434 420 408 430 431 423 426 409 436 435 430 413 426 410 436 422 429 415 414 Consider this data as a sample of the population. (a) Calculate a point estimate of the mean oxide thickness for all wafers in the population. (Round your answer to 3 decimal places.) (b) Calculate a point estimate of the standard deviation of oxide thickness for all wafers...
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Data on oxide thickness of semiconductors are as follows: 426 433 414 418 420 437 416 409 432 436 422 426 412 435 434 427 409 426 407 436 422 426 415 416 Consider this data as a sample of the population. (a) Calculate a point estimate of the mean oxide thickness for all wafers in the population. (Round your answer to 3 decimal places.) (b) Calculate a point estimate of the standard deviation of oxide thickness for all wafers...
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