In: Statistics and Probability
a)
Let X : police response time is normally distributed with mean = 11.2 and standard deviation = 2.1
We asked P( 7 < X < 13) = P[7-/ < X -/ < 13-/ ]
=P[(7-11.2)/2.1 < Z < (13 - 11.2)/2.1]
=P( -2 < Z < 0.86)
= P ( Z < 0.86 ) - P( Z < -2)
= 0.8051 - 0.0228
P( 7 < X < 13 ) = 0.7823
b) P( X < 7 ) = P [ X - / < 7 - 11.2/2.1]
P( X < 7 ) = P( Z < -2)
P( X < 7 ) = 0.0228
c) P( X > 13 ) = P[ X - / > 13 - 11.2/2.1]
P( X > 13) = P( Z > 0.86)
= 1 - P( Z < 0.86)
P( X > 13 ) = 1 - 0.8051
P( X > 13) = 0.1949