In: Statistics and Probability
Police response time to an emergency call is the difference between the time the call is first received by the dispatcher and the time a patrol car radios that it has arrived at the scene. Over a long period of time, it has been determined that the police response time has a normal distribution with a mean of 6.4 minutes and a standard deviation of 1.7 minutes. For a randomly received emergency call, find the following probabilities. (Round your answers to four decimal places.)
(a) the response time is between 3 and 8 minutes
(b) the response time is less than 3 minutes
(c) the response time is more than 8 minutes
solution
(A)P(3< x <8 ) = P[(3-6.4) /1.7 < (x - ) / < (8-6.4) /1.7 )]
= P( -2< Z <0.94 )
= P(Z <0.94 ) - P(Z <-2 )
Using z table
= 0.8264-0.0228
probability= 0.8036
(B)
P(X< 3) = P[(X- ) / < (3-6.4) /1.7 ]
= P(z <-2 )
Using z table
=0.0228
probability=0.0228
(C)
P(x > 8) = 1 - P(x<8 )
= 1 - P[(x -) / < (8-6.4) /1.7 ]
= 1 - P(z < 0.94)
Using z table
= 1 -0.8264
probability= 0.1736