In: Statistics and Probability
Researchers believe that learning through video imitation will
improve self-care skills. For 6 months the researchers worked with
mentally impaired individuals in which half were taught self-care
skills through video imitation and the other half through physical
guidance. At the end of the 6 months, individuals were asked to
independently perform the self-care task and were rated on the
level of required assistance where a higher score indicates more
assistance. What can be concluded with an α of 0.05? The rating
data are below.
video imitation | physical guidance |
15 13 16 17 19 15 16 14 20 |
10 10 17 11 11 14 11 14 16 |
a) What is the appropriate test statistic?
---Select One--- (na, z-test, One-Sample t-test,
Independent-Samples t-test, or Related-Samples t-test)
b)
Condition 1:
---Select One--- (video imitation, self-care
skills, physical guidance, 6 months, or mentally impaired)
Condition 2:
---Select One--- (video imitation, self-care
skills, physical guidance, 6 months, or mentally impaired)
c) Obtain/compute the appropriate values to make a
decision about H0.
(Hint: Make sure to write down the null and alternative hypotheses
to help solve the problem.)
critical value = ______ ; test
statistic = _______
Decision: ---Select One--- (Reject
H0 or Fail reject H0)
d) If appropriate, compute the CI. If not
appropriate, input "na" for both spaces below.
[ ____ , _____ ]
e) Compute the corresponding effect size(s) and
indicate magnitude(s).
If not appropriate, input and/or select "na" below.
d =_____ ; ---Select One---
(na, trivial effect, small effect, medium effect, or large
effect)
r2 = ____ ; ---Select
One--- (na, trivial effect, small effect, medium effect,
or large effect)
f) Make an interpretation based on the results.
Which is correct?
a) Self-care skills improve when learned through physical guidance.
b)Self-care skills improve when learned through video imitation.
c)There is no significant self-care difference between video imitation and physical guidance.