When people smoke, nicotine is converted to cotinine, which can be measured. A sample of 40...

When people smoke, nicotine is converted to cotinine, which can be measured. A sample of 40 smokers has a mean cotinine level of 172.5. Assuming that the standard deviation is known to be 119.5, find a confidence interval estimate of 90% of the mean cotinine level for all smokers. What aspect of this problem is not realistic?

Solutions

Expert Solution

Solution :

Given that,

Point estimate = sample mean = = 172.5

Population standard deviation = = 119.5
Sample size = n =40

At 90% confidence level the z is

= 1 - 90% = 1 - 0.90 = 0.1

/ 2 = 0.1 / 2 = 0.05

Z/2 = Z0.05 = 1.645 ( Using z table )

Margin of error = E = Z/2 * ( / $\sqrt$ n)

= 1.645 * ( 119.5 / $\sqrt$ 40)

E= 31.0816
At 90% confidence interval estimate of the population mean
is,

- E < < + E

172.5 - 31.0816 < <172.5 +31.0816

141.4184 < < 203.5816

( 141.4184 , 203.5816 )

orchestra answered 2 years ago

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