In: Statistics and Probability
A population of values has a normal distribution with
μ=153.5μ=153.5 and σ=17.7σ=17.7. You intend to draw a random sample
of size n=31n=31.
Find the probability that a single randomly selected value is less
than 153.8.
P(X < 153.8) =
Find the probability that a sample of size n=31n=31 is randomly
selected with a mean less than 153.8.
P(M < 153.8) =
Enter your answers as numbers accurate to 4 decimal places. Answers
obtained using exact z-scores or z-scores rounded
to 3 decimal places are accepted.
Solution :
Given that ,
mean = = 153.5
standard deviation = = 17.7
P(x < 153.8) = P[(x - ) / < (153.8 - 153.5) / 17.7 ]
= P(z <0.017 )
Using z table,
= 0.5068
n = 31
= = 153.5
= / n = 17.7/ 31 = 3.179
P(M < 153.8) = P((M - ) / < (153.8 - 153.5) / 3.179 )
= P(z < 0.094)
Using z table
= 0.5374