In: Statistics and Probability
The effectiveness of a blood-pressure drug is being investigated. An experimenter finds that, on average, the reduction in systolic blood pressure is 54.7 for a sample of size 22 and standard deviation 17.5. Estimate how much the drug will lower a typical patient's systolic blood pressure (using a 90% confidence level). Assume the data is from a normally distributed population. Enter your answer as a tri-linear inequality accurate to three decimal places
answer ____ < μμ < ____ answer
Solution :
Given that,
Point estimate = sample mean =
= 54.7
sample standard deviation = s = 17.5
sample size = n = 22
Degrees of freedom = df = n - 1 = 22 - 1 = 21
At 90% confidence level the t is ,
= 1 - 90% = 1 - 0.90 = 0.1
/ 2 = 0.1 / 2 = 0.05
t
/2,df = t0.05,21 = 1.721
Margin of error = E = t/2,df
* (s /
n)
= 1.721 * (17.5 /
22)
= 6.421
The 90% confidence interval estimate of the population mean is,
- E <
<
+ E
54.7 - 6.421 <
< 54.7 + 6.421
48.297 <
< 61.121