In: Statistics and Probability
2. Data, which may be found in the Excel file named “Luggage” on the course Canvas Site (Chapter 10 Data Files), gives the weights (in pounds) of randomly selected checked bags for an airline’s International and Domestic flights on the same day.
| International | Domestic | 
| 39 | 29 | 
| 54 | 36 | 
| 46 | 33 | 
| 39 | 34 | 
| 69 | 38 | 
| 47 | 37 | 
| 48 | 33 | 
| 28 | 29 | 
| 54 | 43 | 
| 62 | 39 | 
| 43 | |
| 42 | |
| 32 | |
| 35 | |
| 39 | 

   
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5. Decision = Reject Ho, Since 6.74 is greater than 3.21
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6 . P-value = 0.002
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7. Conclusion = we have enough evidence to conclude that population variances are not equal.
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Minitab output
Test and CI for Two Variances: International, Domestic
Method
| σ₁: standard deviation of International | 
| σ₂: standard deviation of Domestic | 
| Ratio: σ₁/σ₂ | 
| F method was used. This method is accurate for normal data only. | 
Descriptive Statistics
| Variable | N | StDev | Variance | 95% CI for σ² | 
| International | 10 | 11.890 | 141.378 | (66.888, 471.191) | 
| Domestic | 15 | 4.580 | 20.981 | (11.246, 52.185) | 
Ratio of Variances
| 
Estimated Ratio  | 
95% CI for Ratio using F  | 
| 6.73839 | (2.100, 25.592) | 
Test
| Null hypothesis | H₀: σ₁² / σ₂² = 1 | 
| Alternative hypothesis | H₁: σ₁² / σ₂² ≠ 1 | 
| Significance level | α = 0.05 | 
| Method | 
Test Statistic  | 
DF1 | DF2 | P-Value | 
| F | 6.74 | 9 | 14 | 0.002 | 
Test and CI for Two Variances: International, Domestic
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2.
Two-Sample T-Test and CI: International, Domestic
Method
| μ₁: mean of International | 
| µ₂: mean of Domestic | 
| Difference: μ₁ - µ₂ | 
Equal variances are not assumed for this analysis.
Descriptive Statistics
| Sample | N | Mean | StDev | SE Mean | 
| International | 10 | 48.6 | 11.9 | 3.8 | 
| Domestic | 15 | 36.13 | 4.58 | 1.2 | 
Estimation for Difference
| Difference | 
95% Lower Bound for Difference  | 
| 12.47 | 5.32 | 
Test
| Null hypothesis | H₀: μ₁ - µ₂ = 0 | 
| Alternative hypothesis | H₁: μ₁ - µ₂ > 0 | 
| T-Value | DF | P-Value | 
| 3.16 | 10 | 0.005 | 
Since p-value is less than 0.05 so, reject the null hypothesis and we can conclude that the International mean is greater than Domestic mean