A botanist who loves the smell of the plant Titan arum sets up the following cross....

A botanist who loves the smell of the plant Titan arum sets up the following cross. They mate a wild type pure-breeding Titan arum trisomic for chromosome 5 to a normal diploid Titan arum that is homozygous for a recessive mutation (s) that makes it smell even more aromatic all the time (the super smelly mutant). A trisomic F1 plant is then back-crossed to the super-smelly parent. From this cross:

A] What is the ratio of wild type Titan arum to those that are super smelly when you assume that s is situated on chromosome 5?

B] What is the ratio of wild type Titan arum to those that are super smelly when you assume that s is not situated on chromosome 5?

Solutions

Expert Solution

Parents- phenotype trisomy wild x super smelly

genotype- SSS ss

Gametes - SS , S s

cross-

	SS	S
s	SSs - trisomy	Ss - normal diploid

F2 cross,

Parents - phenotype trisomy x super smelly

genotype SSs ss

Gametes SS, Ss, S, s s

cross,

	SS	Ss	S	s
s	SSs	Sss	Ss	ss

a) super smelly condition , will be expressed only in ss condition.

if the s is present on chromosome number 5,

then, obtained progenies will be - SSs- trisomy , Sss- super smelly(as s is in 5th chromsome, ss will be get expressed), Ss- normal diploid condition, ss - super smelly.

number of wild type arum in the progeny = 1

number of super smelly arum in the progeny = 2

total number of progeny obtained = 4

ratio of wild type arum to super smelly = 1/2 = 0.5

b) if the s is not present on chromosome number 5 , then ss in he trisomy condition won't be expressed,

then obtained progenies will be- SSs- trisomy, Sss- trisomy, Ss- normal diploid, ss- super smelly

number of wild type arum in the progeny = 2

number of super smelly arum in the progeny = 1

ratio of wild type arum to super smelly arum = 2/1 = 2

gladiator answered 1 year ago

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