In: Biology
You set up a cross using two corn plants with green seedlings and obtain the following progeny (6 points):
3583 green seedlings
853 white seedlings
260 yellow seedlings
c. Perform a Chi-square analysis to test the hypothesis stated in part (b) of this question
a & b).
3583 : 853 : 260 is more or less to similar witu 12:3:1 ratio. This ratio appears in dominant epistasis.
When a dominant allele at one locus can mask the expression of both alleles (dominant and recessive) at another locus, it is known as dominant epistasis.
Explanation:
Green = A_B_ or A_bb
White = aaB_
yellow = aabb
c).
AaBb (green) x AaBb (green)---Parents
Aa x Aa = A_ (3/4) & aa (1/4)
Bb x Bb = B_ (3/4) & bb (1/4)
A_B_ = 3/4 * 3/4 = 9/16
A_bb = 3/4 * 1/4 = 3/16
Green = A_B_ + A_bb =9/16 + 3/16 = 12/16
White = aaB_ = 1/4 * 3/4= 3/16
Yellow = aabb = 1/4 * 1/4 = 1/16
Expected progeny:
Total progeny = 4696
Green = 12/16*4696 = 3522
White = 3/16 * 4696 = 880.5
Yellow = 1/16 * 4696 = 293.5
Phenotype | Observed(O) | Expected (E) | O-E | (O-E)2 | (O-E)2/E |
Green | 3583 | 3522 | 61 | 3721.00 | 1.0565 |
White | 853 | 880.5 | -27.5 | 756.25 | 0.8589 |
Yellow | 260 | 293.5 | -33.5 | 1122.25 | 3.8237 |
Total | 4696 | 4696 | 5.7391 |
Chi-square value = 5.74
Degrees of freedom = no. of phenotypes - 1
DF = 3-1=2
P value = 5.99
The chi-square value of 5.74 is less than the p value of 5.99. Hence, null hypothesis is accepted and the populations support the dominant epistasis mode of inheritance.