A solution contains 0.0110 M Pb2 (aq) and 0.0110 M Sr2 (aq). If we add SO42–(aq),...

A solution contains 0.0110 M Pb2 (aq) and 0.0110 M Sr2 (aq). If we add SO42–(aq), what will be the concentration of Pb2 (aq) when SrSO4(s) begins to precipitate?

Expert Solution

Ksp of PbSO4 = 2.53×10^–8

Ksp of SrSO4 = 3.44×10^–7

SrSO4 (s) -------------------> Sr+2 + SO42-

0.0110

Ksp = [Sr+2][SO42-]

3.44 x 10^-7 = 0.0110 x [SO42-]

[SO42-] = 3.13 x 10^-5 M

PbSO4 -------------------> Pb+2 + SO42-

Ksp = [Pb+2][SO42-]

2.53×10^–8 = [Pb+2] (3.13 x 10^-5)

concentration of [Pb+2] = 8.09 x 10^-4 M

queen_honey_blossom answered 2 years ago

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