In: Statistics and Probability
If, in a sample of n=20 selected from a normal population,X=60 and S=12, what is your statistical decision if the level of significance,
α, is 0.01, the null hypothesis,H0, is μ=50, and the alternative hypothesis,H1, μ≠50?
Determine the critical value(s).
The critical value(s) is(are) ____
(Round to four decimal places as needed. Use a comma to separate answers as needed.)
Determine the test statistic, T STAT
T STAT=___
(Round to four decimal places as needed.)
State your statistical decision. Choose the correct answer below.
A.
The test does not reject the null hypothesis. The data provide
sufficient evidence to conclude that the mean differs from
μ=50.
B.
The test rejects the null hypothesis. The data does not provide
sufficient evidence to conclude that the mean differs from
μ=50.
C.
The test does not reject the null hypothesis. The data does not
provide sufficient evidence to conclude that the mean differs from
μ=50.
D.
The test rejects the null hypothesis. The data provide sufficient
evidence to conclude that the mean differs from μ=50.
Solution:
Given:
n = 20
s = 12
Level of significance =
, the null hypothesis,
H0:μ=50, and
the alternative hypothesis,
H1: μ≠50
Since H1 is not equal to type , this is two tailed test.
Part a) Determine the critical value(s).
df = n - 1 = 20 - 1 = 19
Level of significance =
Use following Excel command to get t critical values:
=T.INV.2T(probability, df)
=T.INV.2T(0.01,19)
=2.860935
=2.8609
Thus t critical values are: ( -2.8609 , 2.8609 )
Part b) Determine the test statistic, T STAT
Part c) State your statistical decision.
Since T STAT = 3.7268 > t critical values = 2.8609 , we reject null hypothesis H0. Thus we conclude that mean is different from 50.
Thus correct answer is:
D. The test rejects the null hypothesis. The data provide sufficient evidence to conclude that the mean differs from μ=50.