On a double supported beam with total length of 48” applying 40 lb total load on...

On a double supported beam with total length of 48” applying 40 lb total load on two hangers 6” from each support. If the beam had a rectangular shape with 2” width and .5” thickness what is the stress on each load? With is the maximum deflection at the sender of the beam. E=300000000psi

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Expert Solution

I assume that the beams looks like the following image

For this beam the stress acting at the loaded point can be found by using the following formula

Stress = Load / area

Load = 40 lb (given)

Area = 2*0.5 (given)

Therefore area = 1 in^2

stress = 40/1

= 40 lb/in^2

Deflection at center of the beam:

Formula for deflection of the given beam is

Moment of inertia Ixx = bh^3/12

= 2x0.5^3/12

= 0.02083 in^4

By substituting all the values like P=40lb,E=300000000psi,area,x=24, L=48inch, a=6inch

maximum deflection will be at center so x=24,

therefore the maximum deflection at center is 0.010743 in

samet mamat answered 2 years ago

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