Question

In: Statistics and Probability

Participants Daily Calories Z-Score ( Calories ) Life satisfaction Z-Score ( Satisfaction ) 1 2000 -0.082152426...


Participants

Daily Calories

Z-Score ( Calories )

Life satisfaction

Z-Score ( Satisfaction )

1

2000

-0.082152426

10

1.472538182

2

3000

1.155082909

8

0.825268652

2

1500

-0.700770094

3

-0.792905175

4

1800

-0.329599493

10

1.472538182

5

3200

1.402529976

5

-0.145635644

6

1600

-0.57704656

4

-0.46927041

7

3100

1.278806442

1

-1.440174706

8

2500

0.536465241

6

0.177999121

9

2500

0.536465241

10

1.472538182

10

1900

-0.20587596

3

-0.792905175

11

1500

-0.700770094

4

-0.46927041

12

2900

1.031359375

7

0.501633886

13

3900

2.26859471

2

-1.11653994

14

2500

0.536465241

5

-0.145635644

15

3400

1.649977042

6

0.177999121

16

4000

2.392318243

0

-1.763809471

17

4200

2.63976531

8

0.825268652

18

2050

-0.020290659

7

0.501633886

19

2700

0.783912308

9

1.148903417

20

3030

1.192199969

1

-1.440174706

For the number of daily calories consumed and life satisfaction report the z-scores for participants number 2,6 and 7 . Discuss where these participants scored in relation to the mean and explain how you know the information.

Calculate what raw score was equal to a z score of -1

Using the z table explain what percentage of the distribution scored below this score

Calculate z-scores for these participants 2,6,7 using the z-score formula

Rearrange the formula to figure out what raw scores corresponds with a Z-SORE OF -1

Solutions

Expert Solution

We know that z score = (x-mean)/standard deviation

that is x = mean z score * standard deviations

Thus if z score is positive , x is z score * standard deviations times more than mean

if z score is negative  , x is z score * standard deviations times less  than mean

In short , if x is more than mean z score is positive or else negative

Here x means number of daily calories / life satisfaction

For participant number 2 , z score for Calories is  1.155082909 . That is participant number 2 scored 1.16 times standard deviations more than mean .

For participant number 2 , z score for Life satisfaction is 0.825268652 . That is participant number 2 scored 0.83 times standard deviations more than mean .

For participant number 6 , z score for Calories is -0.577... . That is participant number 6 scored 0.58 times standard deviations less than mean .

For participant number 6 , z score for Life satisfaction is -0.469.... . That is participant number 6 scored 0.47 times standard deviations less than mean .

For participant number 7 , z score for Calories is 1.2788... . That is participant number 6 scored 1.28 times standard deviations more than mean .

For participant number 7 , z score for Life satisfaction is -1.44.... . That is participant number 7 scored 1.44 times standard deviations less than mean .

z score =-1

raw score =?

Let us find raw score of daily calories

for participant number 2

raw score , x = 3000 , z score = 1.155082909

  

for participant number 6

raw score , x = 1600 , z score = -0.57704656

Solving two equations , we get

s= 808.25

Thus for z score = -1

raw score = 2066.40 -808.25 = 1258.15

Let us find raw score of life satisfaction  

for participant number 2

raw score , y=8 , z score =0.8252686

  

for participant number 6

raw score , y=4 , z score = -0.46927041

Solving two equations , we get

s= 3.09

Thus for z score = -1

raw score = 5.45-3.09 = 2.36

From z table , we know that P( z < -1 ) = 0.1587

Thus 15.87 % scored below 1258.15 (daily calories)

15.87% scored below 2.36 ( life satisfaction)

To find z score for participants

Let us find mean and standard deviation from the given sample

mean

standard deviation

x (x-2664)^2 y (y-5.45)^2
2000 440896 10 20.7025
3000 112896 8 6.5025
1500 1354896 3 6.0025
1800 746496 10 20.7025
3200 287296 5 0.2025
1600 1132096 4 2.1025
3100 190096 1 19.8025
2500 26896 6 0.3025
2500 26896 10 20.7025
1900 583696 3 6.0025
1500 1354896 4 2.1025
2900 55696 7 2.4025
3900 1527696 2 11.9025
2500 26896 5 0.2025
3400 541696 6 0.3025
4000 1784896 0 29.7025
4200 2359296 8 6.5025
2050 376996 7 2.4025
2700 1296 9 12.6025
3030 133956 1 19.8025
sum 53280 13065480 109 190.95
mean 2664 5.45
s^2 687656.8 10.05
s 829.2508 3.170173

Thus

Therefore

and

Participant x z score y z score
2 3000 0.405185 2 -1.08833
6 1600 -1.28309 4 -0.45741
7 3100 0.525776 1 -1.40379

z score = -1

raw score , x = -1 * 829.25 +2664 = 1834.75

z score =-1

raw score , y = -1* 3.17+5.45 = 2.28


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