In: Statistics and Probability
Participants |
Daily Calories |
Z-Score ( Calories ) |
Life satisfaction |
Z-Score ( Satisfaction ) |
1 |
2000 |
-0.082152426 |
10 |
1.472538182 |
2 |
3000 |
1.155082909 |
8 |
0.825268652 |
2 |
1500 |
-0.700770094 |
3 |
-0.792905175 |
4 |
1800 |
-0.329599493 |
10 |
1.472538182 |
5 |
3200 |
1.402529976 |
5 |
-0.145635644 |
6 |
1600 |
-0.57704656 |
4 |
-0.46927041 |
7 |
3100 |
1.278806442 |
1 |
-1.440174706 |
8 |
2500 |
0.536465241 |
6 |
0.177999121 |
9 |
2500 |
0.536465241 |
10 |
1.472538182 |
10 |
1900 |
-0.20587596 |
3 |
-0.792905175 |
11 |
1500 |
-0.700770094 |
4 |
-0.46927041 |
12 |
2900 |
1.031359375 |
7 |
0.501633886 |
13 |
3900 |
2.26859471 |
2 |
-1.11653994 |
14 |
2500 |
0.536465241 |
5 |
-0.145635644 |
15 |
3400 |
1.649977042 |
6 |
0.177999121 |
16 |
4000 |
2.392318243 |
0 |
-1.763809471 |
17 |
4200 |
2.63976531 |
8 |
0.825268652 |
18 |
2050 |
-0.020290659 |
7 |
0.501633886 |
19 |
2700 |
0.783912308 |
9 |
1.148903417 |
20 |
3030 |
1.192199969 |
1 |
-1.440174706 |
For the number of daily calories consumed and life satisfaction report the z-scores for participants number 2,6 and 7 . Discuss where these participants scored in relation to the mean and explain how you know the information.
Calculate what raw score was equal to a z score of -1
Using the z table explain what percentage of the distribution scored below this score
Calculate z-scores for these participants 2,6,7 using the z-score formula
Rearrange the formula to figure out what raw scores corresponds with a Z-SORE OF -1
We know that z score = (x-mean)/standard deviation
that is x = mean z score * standard deviations
Thus if z score is positive , x is z score * standard deviations times more than mean
if z score is negative , x is z score * standard deviations times less than mean
In short , if x is more than mean z score is positive or else negative
Here x means number of daily calories / life satisfaction
For participant number 2 , z score for Calories is 1.155082909 . That is participant number 2 scored 1.16 times standard deviations more than mean .
For participant number 2 , z score for Life satisfaction is 0.825268652 . That is participant number 2 scored 0.83 times standard deviations more than mean .
For participant number 6 , z score for Calories is -0.577... . That is participant number 6 scored 0.58 times standard deviations less than mean .
For participant number 6 , z score for Life satisfaction is -0.469.... . That is participant number 6 scored 0.47 times standard deviations less than mean .
For participant number 7 , z score for Calories is 1.2788... . That is participant number 6 scored 1.28 times standard deviations more than mean .
For participant number 7 , z score for Life satisfaction is -1.44.... . That is participant number 7 scored 1.44 times standard deviations less than mean .
z score =-1
raw score =?
Let us find raw score of daily calories
for participant number 2
raw score , x = 3000 , z score = 1.155082909
for participant number 6
raw score , x = 1600 , z score = -0.57704656
Solving two equations , we get
s= 808.25
Thus for z score = -1
raw score = 2066.40 -808.25 = 1258.15
Let us find raw score of life satisfaction
for participant number 2
raw score , y=8 , z score =0.8252686
for participant number 6
raw score , y=4 , z score = -0.46927041
Solving two equations , we get
s= 3.09
Thus for z score = -1
raw score = 5.45-3.09 = 2.36
From z table , we know that P( z < -1 ) = 0.1587
Thus 15.87 % scored below 1258.15 (daily calories)
15.87% scored below 2.36 ( life satisfaction)
To find z score for participants
Let us find mean and standard deviation from the given sample
mean
standard deviation
x | (x-2664)^2 | y | (y-5.45)^2 | ||
2000 | 440896 | 10 | 20.7025 | ||
3000 | 112896 | 8 | 6.5025 | ||
1500 | 1354896 | 3 | 6.0025 | ||
1800 | 746496 | 10 | 20.7025 | ||
3200 | 287296 | 5 | 0.2025 | ||
1600 | 1132096 | 4 | 2.1025 | ||
3100 | 190096 | 1 | 19.8025 | ||
2500 | 26896 | 6 | 0.3025 | ||
2500 | 26896 | 10 | 20.7025 | ||
1900 | 583696 | 3 | 6.0025 | ||
1500 | 1354896 | 4 | 2.1025 | ||
2900 | 55696 | 7 | 2.4025 | ||
3900 | 1527696 | 2 | 11.9025 | ||
2500 | 26896 | 5 | 0.2025 | ||
3400 | 541696 | 6 | 0.3025 | ||
4000 | 1784896 | 0 | 29.7025 | ||
4200 | 2359296 | 8 | 6.5025 | ||
2050 | 376996 | 7 | 2.4025 | ||
2700 | 1296 | 9 | 12.6025 | ||
3030 | 133956 | 1 | 19.8025 | ||
sum | 53280 | 13065480 | 109 | 190.95 | |
mean | 2664 | 5.45 | |||
s^2 | 687656.8 | 10.05 | |||
s | 829.2508 | 3.170173 |
Thus
Therefore
and
Participant | x | z score | y | z score |
2 | 3000 | 0.405185 | 2 | -1.08833 |
6 | 1600 | -1.28309 | 4 | -0.45741 |
7 | 3100 | 0.525776 | 1 | -1.40379 |
z score = -1
raw score , x = -1 * 829.25 +2664 = 1834.75
z score =-1
raw score , y = -1* 3.17+5.45 = 2.28