Question

An Office of Admissions document claims that 56.1% of UVA undergraduates are female. To test whether this claim is accurate, a random sample of 220 UVA undergraduates was selected. In this sample, 53.6364% were female. Is there sufficient evidence to conclude that the document's claim is false? Carry out a hypothesis test at a 10% significance level.

A. The p-value is

B. Your decision for the hypothesis test:

A. Do Not Reject H1H1.
B. Reject H0H0.
C. Reject H1H1.
D. Do Not Reject H0H0.

Also, can you do the calculations for finding the p-value on TI-83? Thanks!

Answer 1

This is a Z test for proportion

We have to test the claim that the proportion of UVA undergraduates that are female sis 0.561 or not.

A) The P value is 0.4615

B) The decision about for the test is that the hypothesis test is not significant we have no evidence to reject the claim that the proportion of UVA undergraduates that are female is other than 0.561.

Option Do Not Reject D is right H0

We can find the P-value using the

Normalcdf feature of the calculator, that can be found by pressing .

Calculator would expect following:

Normalcdf (lowerbound, upperbound).

Type in: Normalcdf(-100, -0.736) ,

after you have pressed [ENTER] you should get the P value for the left tailed test.

Remember this is a two tailed test, and above you have calculated the P value for the left tailed test. hence you need to multiply it by 2 to get the same p-value as above.