In: Statistics and Probability
A random sample of 500 male and female adults was asked the amount of time each person spent watching TV last week. Their responses are shown at the right. At the 0.05 significance level, does it appear that the amount of time spent watching TV is related to the gender of the viewer?
Hours/Gender | Male | Female | Total |
Under 8 | 90 | 110 | 200 |
8 to 15 | 85 | 75 | 160 |
15 or more | 75 | 65 | 140 |
Total | 250 | 250 | 500 |
Which test would be used to properly analyze the data in this experiment?
χ 2 test for difference among more than two proportions |
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none of the above |
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χ 2 test for difference between two proportions |
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χ 2 test of independence |
answer only !!
We want to test the amount of time spent watching TV is related to the gender of the viewer.
To Analyze the data in this experiment the chi-square( χ 2) test of independence is appropriate.
Hypothesis:
H0 : The amount of time spent watching TV is not related to the gender of the viewer.
Against
H0 : The amount of time spent watching TV is not related to the gender of the viewer.
Test statistic:
Where,
m= number of rows= 3
n=number of columns=2
N=grand total
Eij =expected frequency of ith row and jth column
Observation table:
O12 =110
Hours\Gender | Male | Female | Row total |
Under 8 | O11 =90 | R1= 200 | |
8 to 15 | O21 = 85 | O22 = 75 | R2=160 |
15 or more | O31 =75 | O32 = 65 | R3=140 |
Column total | C1=250 | C2= 250 | N=500 |
Observation table:
Oij | Eij | O2ij / E ij |
90 | 100 | 81 |
110 | 100 | 121 |
85 | 80 | 90.3125 |
75 | 80 | 70.3125 |
75 | 70 | 80.3571 |
65 | 70 | 60.3571 |
=503.3392 |
The calculated test statistic is
Critical value at (m-1)(n-1)=(3-1)(2-1)=2*1=2 degrees of freedom at 5% level of Significance is:
Therefore we failed to reject the null hypothesis at 5% level of Significance.
Conclusion:
There insufficient evidence to conclude that the amount of time spent watching TV is related to the gender of the viewer.