Question

In: Statistics and Probability

In a test of the effectiveness of garlic for lowering​ cholesterol, 36 subjects were treated with...

In a test of the effectiveness of garlic for lowering​ cholesterol, 36 subjects were treated with raw garlic. Cholesterol levels were measured before and after the treatment. The changes​ (before minus​ after) in their levels of LDL cholesterol​ (in mg/dL) have a mean of 0.7 and a standard deviation of 20.1. Use a 0.10 significance level to test the claim that with garlic​ treatment, the mean change in LDL cholesterol is greater than 0. What do the results suggest about the effectiveness of the garlic​ treatment? Assume that a simple random sample has been selected. Identify the null and alternative​ hypotheses, test​ statistic, P-value, and state the final conclusion that addresses the original claim. What are the null and alternative​ hypotheses?

Determine the test statistic.

Determine the​ P-value.

Solutions

Expert Solution

H0: = 0

H1: > 0

The test statistic t = ( - D)/(sd/)

                              = (0.7 - 0)/(20.1/)

                              = 0.21

P-value = P(T > 0.21)

              = 1 - P(T < 0.21)

              = 1 - 0.5826

              = 0.4174


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