A bee was flying along a helical path so that its position vector at time t...

A bee was flying along a helical path so that its position vector at time t was r(t) = (5 cos t) i + (5 sin t) j + 2t k. At t = 4 sec it had a heart attack and died instantly. Where did it land (that is where did it hit the xy-plane in terms of its coordinates)? Assume distance is in feet and time is in seconds so g = 32 ft per second per second.

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Expert Solution

When bee got dead it will fall freely under gravity. There will be only one acceleration of been that will be acceleration due to gravity I downward direction. There we will calculate the position and the velocity of bee at t=4 sec. Then we will calculate the time taken by bee to reach on the xy plane after it got heart attack by considering the motion of bee along z axis. Then we will calculate x coordinate of bee by analyzing the motion of bee in x direction for that duration and in the similar way we will calculate the y coordinate of bee where it will land.

genius_generous answered 1 year ago

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