In: Statistics and Probability
The authors of a paper concerned about racial stereotypes in television counted the number of times that characters of different ethnicities appeared in commercials aired on a certain city's television stations, resulting in the data in the accompanying table.
Ethnicity |
African- American |
Asian | Caucasian | Hispanic |
---|---|---|---|---|
Observed Frequency | 58 | 12 | 322 | 6 |
Based on the 2000 Census, the proportion of the U.S. population
falling into each of these four ethnic groups are 0.177 for
African-American, 0.032 for Asian, 0.734 for Caucasian, and 0.057
for Hispanic. Do the data provide sufficient evidence to conclude
that the proportions appearing in commercials are not the same as
the census proportions? Test the relevant hypotheses using a
significance level of 0.01.
Let p1, p2,
p3, and p4 be the
proportions of appearances of the four ethnicities across all
commercials.
Calculate the test statistic. (Round your answer to two decimal
places.)
χ2 = __
What is the P-value for the test? (Round your answer to
four decimal places.)
P-value = __
Solution:
The given data is as shown below.
Ethnicity | Observed frequency(Oi) |
African-American | 58 |
Asian | 12 |
Caucasian | 322 |
Hispanic | 6 |
Let p1, p2, p3, and p4 be the proportions of appearances of the four ethnicities across all commercials.
Step 1:State the null and alternative hypothesis.
Null hypothesis:Ho:p1=0.177,p2=0.032 ,p3=0.734 and p4=0.057
and Alternative hypothesis:Ha: Atleast one of the population proportions is not equal to its corresponding hypothesized proportion.
Step 2:Degree of freedom and level of significance
DF=k-1=4-1=3 where DF is the degrees of freedom, k is the number of levels of the categorical variable
and level of significance,=0.01
Step 3:Calculation of test statistics
The test statistics,X2=(Oi-Ei)2/Ei
The below table shows the values required to calculate the test statistics.
Ethnicity | Observed frequency(Oi) | Proportions | Expected frequency(Ei) | (Oi-Ei) | (Oi-Ei)2 | (Oi-Ei)2/Ei |
African-American | 58 | 0.177 | 398*0.177=70.446 | -12.446 | 154.9029 | 2.199 |
Asian | 12 | 0.032 | 398*0.032=12.736 | -0.736 | 0.541696 | 0.043 |
Caucasian | 322 | 0.734 | 398*0.734=292.132 | 29.868 | 892.0974 | 3.054 |
Hispanic | 6 | 0.057 | 398*0.057=22.686 | -16.686 | 278.4226 | 12.273 |
Total | 398 | 398 | 17.568 |
Substituting the values form the table in the formula,X2=(Oi-Ei)2/Ei
=17.568
X2=17.57(round to 2 decimal places)
Step 4:Determination of X2 critical value.
The Chi-square distribution table is as shown below.
For DF=3 and =0.01, the X2 critical value=11.345
Step 5:Conclusion
Since X2 observed value=17.5 which is greater than the X2 critical value=11.345, we reject the null hypothesis and conclude that atleast one of the population proportions is not equal to its corresponding hypothesized proportion.
Calculation of P-value.
The P-value is 0.0005.