Question

This is done in C++.

This is a game where one player thinks of a number between 1 and a 1000 and the other player has to guess in 10 tries or less.

Allow two variations: the computer to pick the number and the player guesses or the player to pick the number and the computer to guesses.

1 – Player one picks a number

2 – Player two guesses the number.

3 – Player one either confirms that the guess is correct or tells whether the guess is too high or too low.

4 – Steps 2 and 3 are repeated until count of 10 or the number is guessed correctly.

Notice that you are writing a binary search as you are searching natural numbers from1 to 1000. You may want to make it 1024 since 2¹⁰ = 1024. This is a sorted array.

Answer 1

C++. game where one player thinks of a number between 1 and a 1000 and the other player has to guess in 10 tries or less.

CODE:

#include <iostream> //included to allow for cout/cin to be used

#include <cstdlib> //include to allow rand() and srand() to be used

#include <time.h>

using namespace std;

int main()

{

bool cont=true;

while(cont)

{

int count=0; // variable count to track number of guesses

int guess;

srand(time(0)); //seeds random number generator.

int x = rand() % 1000;

cout << "Guess a number between 1 -1000.You have only 10 tries\n"; // prompt user to guess a number

std::cin >> guess;

while (guess !=x && count <= 10) // check whether guess is equal or not and count is less than 10

{

if (guess > x)

{

cout << "Too high! Try again. "<<endl;

cin >> guess;

count++;

}

if (guess < x)

{

cout << "Too low! Try again. "<<endl;

cin>>guess;

count++;

}

if (guess == x)

{

cout << "\n\nYou' guessed it right. Good job! "<<endl;

return 0;

}

if (count==10)

{

cout << "\n\nYou're out of guesses!\n";

cout << "\nThe number was - "<<x;

return 0;

}   

}

}

return 0;

}