1) The average female bobcat weight about 9.6 kg. Let's assume μ = 9.6 and σ...

1) The average female bobcat weight about 9.6 kg. Let's assume μ = 9.6 and σ = 1.75kg. a) Calculate Pr{Y > 11.5} b) Now assume you have a sample of n = 16 male bobcats. Calculate Pr{ Ȳ > 11.5}. c) Which probability is lower? Why? 2) Refer to problem 1. Now assume you take a sample of n = 9 male bobcats. a) What is the probability of the sample average being within 0.5 kg of the population mean (9.6 kg)? In other words, you need to figure out Pr{ μ - .5 < Ȳ < μ + .5} b) What is the probability of the sample average being within 0.5 kg of the population mean if the population mean is actually μ = 10.8 kg? Are you surprised? Why or why not? You should make sure you understand what happened here. c) Now assume a sample of n = 25 male bobcats and repeat (a). What is the effect of sample size?

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orchestra answered 1 year ago

QUATION 2 PLEASE 1) The average female bobcat weight about 9.6 kg. Let's assume μ =...

QUATION 2 PLEASE 1) The average female bobcat weight about 9.6 kg. Let's assume μ = 9.6 and σ = 1.65kg. a) Calculate Pr{Y > 10.3} b) Now assume you have a sample of n = 26 male bobcats. Calculate Pr{ Ȳ > 10.3}. c) Which probability is lower? Why? 2) Refer to problem 1. Now assume you take a sample of n = 4 male bobcats. a) What is the probability of the sample average being within 0.75 kg...

The body weight of a healthy 3-month-old colt should be about μ = 64 kg. (a)...

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1) Average tire life is 30,000 miles (μ = 30,000) and σ = 2,300 miles. What is the...

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SEX: Sex (1=Male 2=Female) WEIGHT: Body Weight (kg) 1 61.236 1 79.38 1 99.792 1 81.648...

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Let's assume your process yields products with a mean diameter of 12.50mm and σ = 0.010mm....

Let's assume your process yields products with a mean diameter of 12.50mm and σ = 0.010mm. If the specification calls for a range of 12.480mm - 12.530mm, what percentage of parts will have a diameter within these limits?

Assume Y is a normally distributed population with unknown mean, μ, and σ = 25. If...

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Two-Sample T-Test and CI: Weight, Gender Method μ₁: mean of weight when Gender = Female µ₂:...

Two-Sample T-Test and CI: Weight, Gender Method μ₁: mean of weight when Gender = Female µ₂: mean of weight when Gender = Male Difference: μ₁ - µ₂ Equal variances are not assumed for this analysis. Descriptive Statistics: Weight Gender : N ---- Mean ----- StDev Female : 315 ----- 170 ------- 50 Male : 42 ----- 196 -------- 65 Test Null hypothesis H₀: μ₁ - µ₂ = 0 Alternative hypothesis H₁: μ₁ - µ₂ ≠ 0 T-Value P-Value ----- ...

1. Assume that the average weight of an NFL player is 245.7 lbs with a standard...

1. Assume that the average weight of an NFL player is 245.7 lbs with a standard deviation of 34.5 lbs. The distribution of NFL weights is not normal. Suppose you took a random sample of 32 players. What is the probability that the sample average will be between 242 and 251 lbs? Round your answer to three decimal places, eg 0.192. 2. Given a sample with a mean of 57 and a standard deviation of 8, calculate the following probabilities...

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