In: Statistics and Probability
The diameters of steel shafts produced by a certain manufacturing process should have a mean diameter of 0.218 inches. The diameter is known to have a standard deviation of = 0.0003 inch. A random sample of 40 shafts has an average diameter of 0.2455 inches.
a/ Test these hypotheses using α= 0.02, α= 0.05, and α= 0.09
b/ Comparing the data above. Does the results of your hypothesis testing change when you changed α? Explain.
Please show your work and explain. Thanks.
Solution-A:
Ho:mu=0.218
Ha:mu not =0.218
alpha=0.02
test statistic
z=xbar-mu/igma/sqrt(n)
z=(0.2455-0.218)/0.0003/sqrt(40)
z=579.7509
P value in excel
we get left tail prob by NORM.DIST
and 1-left tail=right tail
2*right tail
=NORM.DIST(579.7509,0,1,TRUE)
=1-1
=0
=2*0
p=0.000
for alpha=0.02
p=0..000
p<alpha,reject null hypothesis at 2% level of significance
for alpha=0.05
p<alpha
reject null hypothesis at 5% level of significance
for alpha=0.09
p<alpha
reject null hypothesis at 9% level of significance
b/ Comparing the data above. Does the results of your hypothesis testing change when you changed α?
No since p=0.000
p<0.02,0.05,0.09
Reject null hypothesis
Conclusion:
there is no sufficient statistical evidence at 2%,5% and 9% level of significance to conclude that
The diameters of steel shafts produced by a certain manufacturing process should have a mean diameter of 0.218 inches