1. An 0.865-mol sample of PCl5 is placed in a 500.-mL reaction vessel. What is the...

1. An 0.865-mol sample of PCl5 is placed in a 500.-mL reaction vessel. What is the concentration of each substance when the reaction PCl5(g) PCl3(g) + Cl2(g) has reached equilibrium at 250 deg Celcius (when Kc = 1.80)?

Expert Solution

PCl5(g) ------------>PCl3(g) + Cl2(g)

I 0.865 0 0

C -x +x +x

E 0.865-x +x +x

[PCl5] = 0.865-x/0.5

[PCl3] = x/0.5

[Cl2] = x/0.5

Kc = [PCl3][Cl2]/[PCl5]

1.8 = x*x/0.5*(0.865-x)

1.8*0.5*(0.865-x) = x^2

x = 0.54

[PCl5] = 0.865-x/0.5 = 0.865-0.54/0.5 = 0.325/0.5 = 0.65M

[PCl3] = x/0.5 = 0.54/0.5 = 1.08M

[Cl2] = x/0.5 = 0.54/0.5 = 1.08M

queen_honey_blossom answered 2 years ago

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