Question

In: Statistics and Probability

A box contains 4 orange pencils, 5 yellow pencils, and 3 green pencils. Two pencils are...

A box contains 4 orange pencils, 5 yellow pencils, and 3 green pencils. Two pencils are selected, one at a time, with replacement. Find the probability that the first pencil is green and the second pencil is yellow. Express your answer as a decimal, rounded to the nearest hundredth.

Solutions

Expert Solution

For finding the probability of two events happening, we must multiply the probability of each separate event happening by the other.

So, for the first time that we pick a pencil, we have to find the probability that it is a green pencil.

Probability = favorable outcomes / total possible outcomes = 3 green / (5 yellow + 3 green +4 orange)

= 3 green pencils / 12 total pencils

Thus, the probability of the first event is 3/12 that is 1/4

According to the question, we want to pick a yellow pencil 2nd time, but we also replace it that is after first event selected pencil is returned to the place from where it was selected . So total pencils is 12 now (no change)

Thus, probability of the second event = probable outcomes/ total outcomes =

5 yellow pencils/(5 yellow +3 green+4 orange pencils)

= 5 / 12

Therefore, the second event's probability is 5/12

To find the total probability, we must multiply the two fractions together.

(1/4) * (5/12) = 5/48

Or we can write 5/48 as 0.104 (rounded)

So required probability of first green then yellow is 5/48


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