Question

In: Statistics and Probability

A sample of 36 patients in a doctor's office showed that they had to wait an...

A sample of 36 patients in a doctor's office showed that they had to wait an average of 45 minutes with a standard deviation of 12 minutes before they could see the doctor.

Please provide a 95% confidence interval estimate for the average waiting time of all the patients who visit this doctor, and interpret your results (write a sentence explaining the results).

Expert Solution

= Solution :

Given that,

sample mean = =45

Population standard deviation = =12

Sample size n =36

At 95% confidence level the z is ,

= 1 - 95% = 1 - 0.95 = 0.05

/ 2 = 0.05 / 2 = 0.025

Z/2 = Z0.025 = 1.96 ( Using z table )

Margin of error = E = Z/2 * ( / $\sqrt$ n)

= 1.96* ( 12/ $\sqrt$ 36 $\sqrt$ )

= 3.92
At 95% confidence interval
is,

- E < < + E

45 - 3.92 < < 45+ 3.92

41.08< < 48.92

lower bound41.08

upper bound48.92

a 95% confidence interval estimate for the average waiting time of all the patients who visit this doctor, and interpret your results 41.08 to 48.92

orchestra answered 2 years ago

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